cos(2π x)
![cosπx的图像怎么画](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=2329506549,2092021978&fm=253&fmt=auto&app=138&f=JPEG?w=375&h=500)
cosπx的图像怎么画
图片尺寸780x1040![y=cos(x π/3)的函数简图](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=1362573596,3921167155&fm=253&fmt=auto&app=138&f=JPEG?w=659&h=353)
y=cos(x π/3)的函数简图
图片尺寸659x353![如何准确画出g(x)=|xcosπx|的图像,包括怎样在区间求出极值.](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=1325715307,1355505581&fm=253&fmt=auto&app=138&f=PNG?w=500&h=531)
如何准确画出g(x)=|xcosπx|的图像,包括怎样在区间求出极值.
图片尺寸570x605![y=2cos1/2x y=2cos(x-π/2) y=cos(1/2x π/4) 这三个函数](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=1295193316,1491325519&fm=253&fmt=auto&app=138&f=JPEG?w=723&h=349)
y=2cos1/2x y=2cos(x-π/2) y=cos(1/2x π/4) 这三个函数
图片尺寸723x349![y=2cos(π/4-x/2)(x∈【0,2π】)的递减区间是?](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=716956573,2441397340&fm=253&fmt=auto&app=138&f=JPEG?w=500&h=313)
y=2cos(π/4-x/2)(x∈【0,2π】)的递减区间是?
图片尺寸600x375![y=-2cos(2x一-3分之兀)的对称轴对称中心](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=2150774977,252944916&fm=253&fmt=auto&app=138&f=JPEG?w=500&h=667)
y=-2cos(2x一-3分之兀)的对称轴对称中心
图片尺寸2448x3264![求y=cos(2x π/3)的最值](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=581822270,1331166&fm=253&fmt=auto&app=138&f=JPEG?w=491&h=166)
求y=cos(2x π/3)的最值
图片尺寸491x166![y=cosx取x=0,π/2,π,3π/2,2π y=cos2x取x=0,π/4,π/2,3π/4,π](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=1602353126,2989715380&fm=253&fmt=auto&app=138&f=JPEG?w=600&h=299)
y=cosx取x=0,π/2,π,3π/2,2π y=cos2x取x=0,π/4,π/2,3π/4,π
图片尺寸600x299![2017-2018学年高中数学北师大版必修4学案:1.](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=1483420598,952321561&fm=253&fmt=auto&app=138&f=PNG?w=1587&h=436)
2017-2018学年高中数学北师大版必修4学案:1.
图片尺寸1587x436![作出函数y=|cos x|,xÎ [0,2π)的简图. _作业帮](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=1521507272,3214496657&fm=253&fmt=auto&app=138&f=GIF?w=298&h=159)
作出函数y=|cos x|,xÎ [0,2π)的简图. _作业帮
图片尺寸298x159![f(x)=cos(2x π/4),且x∈〔0,π〕,求f(x)的单调减区间,求一手过程](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=2727117087,3451278933&fm=253&fmt=auto&app=138&f=JPEG?w=450&h=600)
f(x)=cos(2x π/4),且x∈〔0,π〕,求f(x)的单调减区间,求一手过程
图片尺寸450x600![(x)=√(1-cos2x) =√(2sinx) =√2*|sinx| 显然,f(x)的最小正周期t=π](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=3216597272,4260871997&fm=253&fmt=auto&app=120&f=JPEG?w=975&h=400)
(x)=√(1-cos2x) =√(2sinx) =√2*|sinx| 显然,f(x)的最小正周期t=π
图片尺寸1029x422![试画出函数y=sinx/2|cosx/2| cosx/2|sinx/2|在x∈[-2π,2π]上](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=3569325980,98709453&fm=253&fmt=auto&app=138&f=JPEG?w=600&h=307)
试画出函数y=sinx/2|cosx/2| cosx/2|sinx/2|在x∈[-2π,2π]上
图片尺寸600x307![函数f(x)=3cos(π/2)x-log2x-1/2的零点个数为](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=4195149109,1690126682&fm=253&fmt=auto&app=138&f=JPEG?w=344&h=354)
函数f(x)=3cos(π/2)x-log2x-1/2的零点个数为
图片尺寸344x354![cos(-x 5/兀)单调区间是什么三角函数](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=4009047844,1248904579&fm=253&fmt=auto&app=138&f=JPEG?w=500&h=667)
cos(-x 5/兀)单调区间是什么三角函数
图片尺寸780x1040![函数y =cos ?2x -π3的部分图象可能是](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=858342271,617804483&fm=253&fmt=auto&app=138&f=PNG?w=655&h=397)
函数y =cos ?2x -π3的部分图象可能是
图片尺寸655x397![y=2cos1/2x y=2cos(x-π/2) y=cos(1/2x π/4) 这三个函数](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=3258085253,68673321&fm=253&fmt=auto&app=138&f=JPEG?w=500&h=189)
y=2cos1/2x y=2cos(x-π/2) y=cos(1/2x π/4) 这三个函数
图片尺寸649x245![如图,1,cosx的周期2π](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=2491398830,3222083208&fm=253&fmt=auto&app=138&f=JPG?w=484&h=290)
如图,1,cosx的周期2π
图片尺寸484x290![函数y =cos x (x ∈r)的图象向右平移π2 个单位后,得到函数y =g (x )](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=1406104697,192629137&fm=253&fmt=auto&app=138&f=PNG?w=499&h=188)
函数y =cos x (x ∈r)的图象向右平移π2 个单位后,得到函数y =g (x )
图片尺寸539x203![作出y=2cos(x π/3)的图像](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=1728126415,2504601768&fm=253&fmt=auto&app=138&f=JPEG?w=340&h=189)
作出y=2cos(x π/3)的图像
图片尺寸340x189