cos3π
![题目:已知函数y=asin(ωx φ)(x属于r, a>0, ω>0 , φ的绝对值小于π](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=2920754307,2049029265&fm=253&fmt=auto&app=138&f=JPEG?w=450&h=338)
题目:已知函数y=asin(ωx φ)(x属于r, a>0, ω>0 , φ的绝对值小于π
图片尺寸450x338![教育 > 中学 1 ∫sec(3π/2-α)dα =-∫d(3π/2-α)/ cos(3π/2-α)](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=2595604444,3591600363&fm=253&fmt=auto&app=138&f=JPEG?w=500&h=258)
教育 > 中学 1 ∫sec(3π/2-α)dα =-∫d(3π/2-α)/ cos(3π/2-α)
图片尺寸500x258![=sin(2x θ) √3cos(2x θ) √3-√3 =2sin(2x θ π/3)](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=2831397643,1994273840&fm=253&fmt=auto&app=138&f=PNG?w=500&h=271)
=sin(2x θ) √3cos(2x θ) √3-√3 =2sin(2x θ π/3)
图片尺寸1134x615![【1】如果是:y=1-cos(2x-x/3) 图像如下: 【2】如果是:y=1-cos(2x-π](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=3948022423,2057024606&fm=253&fmt=auto&app=138&f=JPG?w=500&h=299)
【1】如果是:y=1-cos(2x-x/3) 图像如下: 【2】如果是:y=1-cos(2x-π
图片尺寸500x299![67t tcos67ty=cos67t61tsin67tz=t0≤t≤10πt=linspace(0](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=2797592990,2886585800&fm=253&fmt=auto&app=138&f=JPG?w=645&h=500)
67t tcos67ty=cos67t61tsin67tz=t0≤t≤10πt=linspace(0
图片尺寸1044x809![cos(-3/13π)三角函数](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=1978141029,2293127668&fm=253&fmt=auto&app=138&f=JPEG?w=500&h=667)
cos(-3/13π)三角函数
图片尺寸780x1040![求定积分∫[x]cos(πx/3)dx,x∈[0,3]](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=3577125990,673352108&fm=253&fmt=auto&app=138&f=JPEG?w=426&h=353)
求定积分∫[x]cos(πx/3)dx,x∈[0,3]
图片尺寸426x353![n aos2π aintan αcos-a-3t sin/-3tt-cl _百度教育](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=4227204772,547979466&fm=253&fmt=auto&app=138&f=JPEG?w=670&h=386)
n aos2π aintan αcos-a-3t sin/-3tt-cl _百度教育
图片尺寸670x386![公共面积就是这两个部分加起来的.两圆的交点就是(0,0),(π/3,3a/2)](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=496087028,221840979&fm=253&fmt=auto&app=138&f=JPEG?w=577&h=310)
公共面积就是这两个部分加起来的.两圆的交点就是(0,0),(π/3,3a/2)
图片尺寸577x310![三角函数sin,cos,tan,cot,sec,csc,π,2π,3π](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=3524413316,1809496446&fm=253&fmt=auto&app=138&f=PNG?w=402&h=382)
三角函数sin,cos,tan,cot,sec,csc,π,2π,3π
图片尺寸402x382![π](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=1258579947,2459685028&fm=253&fmt=auto&app=138&f=JPEG?w=667&h=500)
π
图片尺寸1080x810![2013-04-08 函数y=sin(2x π/4)和 y=cos(2x-3π/4.](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=396795362,2674906342&fm=253&fmt=auto&app=138&f=JPEG?w=500&h=275)
2013-04-08 函数y=sin(2x π/4)和 y=cos(2x-3π/4.
图片尺寸500x275![参与团队:金榜题名时 向ta提问私信ta 展开全部 =πa∫sinx(3cosx)](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=810313172,186985347&fm=253&fmt=auto&app=138&f=JPEG?w=500&h=838)
参与团队:金榜题名时 向ta提问私信ta 展开全部 =πa∫sinx(3cosx)
图片尺寸573x960![怎么把α-β和α β用2/π α β 3π/4的取值范围表示.详!](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=2735071592,448628472&fm=253&fmt=auto&app=138&f=JPEG?w=512&h=360)
怎么把α-β和α β用2/π α β 3π/4的取值范围表示.详!
图片尺寸512x360![周期为π的偶函数是( )a.y=sin2x b.y=cos c.y=cos2x d.](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=2239812004,3218573629&fm=253&fmt=auto&app=138&f=GIF?w=630&h=278)
周期为π的偶函数是( )a.y=sin2x b.y=cos c.y=cos2x d.
图片尺寸630x278![六分之五π三角函数值?](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=3774367376,1467286686&fm=253&fmt=auto&app=138&f=JPEG?w=500&h=533)
六分之五π三角函数值?
图片尺寸640x682![cos(a π/3)=sin(a-π/3),tana为多少啊](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=428424646,2314801361&fm=253&fmt=auto&app=138&f=JPEG?w=640&h=480)
cos(a π/3)=sin(a-π/3),tana为多少啊
图片尺寸640x480![若锐角θ满足sinθ cosθ,且sinθ cosθ=√6/2,那么tan(θ-π/6)的值](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=3223414788,2060756511&fm=253&fmt=auto&app=138&f=JPG?w=1266&h=500)
若锐角θ满足sinθ cosθ,且sinθ cosθ=√6/2,那么tan(θ-π/6)的值
图片尺寸1352x534![已知π/2 β 3π/4,cos(α-β)=12/13,sin(α β)=-3/5,求sin2α](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=41152590,3092297443&fm=253&fmt=auto&app=138&f=JPEG?w=569&h=500)
已知π/2 β 3π/4,cos(α-β)=12/13,sin(α β)=-3/5,求sin2α
图片尺寸667x586![sino cos2分之π tan3分之π=?](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=2728850770,731869081&fm=253&fmt=auto&app=138&f=JPEG?w=281&h=500)
sino cos2分之π tan3分之π=?
图片尺寸747x1328