cos5π的平方
![已知函数f(x)=cos(x-π/3)-sin(π/2-x).1.求函数的最](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=168071391,2943373848&fm=15&fmt=auto&gp=0.jpg)
已知函数f(x)=cos(x-π/3)-sin(π/2-x).1.求函数的最
图片尺寸600x800![已知cosα=-4/5,α∈(π,3/2π),tanβ=-1/3,β∈(π/2,π),求cos(α](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=573261518,1988840086&fm=26&fmt=auto&gp=0.jpg)
已知cosα=-4/5,α∈(π,3/2π),tanβ=-1/3,β∈(π/2,π),求cos(α
图片尺寸780x1040![设函数fx=sin(2x π/3) √3/3sin05x-√3/3cos05x](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=4129724806,1428401321&fm=15&fmt=auto&gp=0.jpg)
设函数fx=sin(2x π/3) √3/3sin05x-√3/3cos05x
图片尺寸600x612![∫cos(nx)cos(x)dx在(0,pi)上的定积分,我知道可以讲积分项用sin(n 1)](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=910868422,2200206968&fm=26&fmt=auto&gp=0.jpg)
∫cos(nx)cos(x)dx在(0,pi)上的定积分,我知道可以讲积分项用sin(n 1)
图片尺寸450x308![cos5π/12等于多少](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=1310766084,326008809&fm=26&fmt=auto&gp=0.jpg)
cos5π/12等于多少
图片尺寸780x1052![求下列格式的值.(1)cos165°; (2)cos12分之5π](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=1630200752,4142864229&fm=26&fmt=auto&gp=0.jpg)
求下列格式的值.(1)cos165°; (2)cos12分之5π
图片尺寸486x648![求值:sin(-11π/6) cos12π/5*tan4π 1/cos7π/3](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=1862430023,2633909147&fm=26&fmt=auto&gp=0.jpg)
求值:sin(-11π/6) cos12π/5*tan4π 1/cos7π/3
图片尺寸2592x1944![求f(x)=sin(派/3 4x) 根号3cos(4x 派/3)的最小正周期](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=2232611015,3983487611&fm=26&fmt=auto&gp=0.jpg)
求f(x)=sin(派/3 4x) 根号3cos(4x 派/3)的最小正周期
图片尺寸972x1296![高中数学三角函数 图中圈出的cos二分之π减b 怎么得出sin二分之b的?](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=283104789,2439122043&fm=26&fmt=auto&gp=0.jpg)
高中数学三角函数 图中圈出的cos二分之π减b 怎么得出sin二分之b的?
图片尺寸1052x592![=-(1/6)sin^5xcosx-(5/24)sin^3x-(5/16)cosxsinx 5/16x 将π和0分别](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=1470019425,1568588191&fm=26&fmt=auto&gp=0.jpg)
=-(1/6)sin^5xcosx-(5/24)sin^3x-(5/16)cosxsinx 5/16x 将π和0分别
图片尺寸450x364![曲线x=cost,y=sin2t,z=cos3t在t=π/4处的切线方程为?](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=1606136021,2179392057&fm=26&fmt=auto&gp=0.jpg)
曲线x=cost,y=sin2t,z=cos3t在t=π/4处的切线方程为?
图片尺寸640x480![又 sin2α cos2α=1,∴5cos2α=1, ∴cosα=](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=3299977782,3209760852&fm=26&fmt=auto&gp=0.jpg)
又 sin2α cos2α=1,∴5cos2α=1, ∴cosα=
图片尺寸1080x810![已知0 a π/2 b π,cos(b-π/4)=1/3,sin(a b)=4/5.(1](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=3972667471,1631493821&fm=15&fmt=auto&gp=0.jpg)
已知0 a π/2 b π,cos(b-π/4)=1/3,sin(a b)=4/5.(1
图片尺寸2560x1920![ππ 1) z= 12 2i; 2) z= sin i cos .](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=175207435,264998354&fm=26&fmt=auto&gp=0.jpg)
ππ 1) z= 12 2i; 2) z= sin i cos .
图片尺寸1077x808![己知cosθ=-3/5,且θ∈(兀,3/2兀),求cosθ/2的值](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=2121740794,2158714326&fm=26&fmt=auto&gp=0.jpg)
己知cosθ=-3/5,且θ∈(兀,3/2兀),求cosθ/2的值
图片尺寸780x1040![已知cos(派/6-x)=根号3/3求cos(5/6派 x)-sin平方(x-派/6)的值](https://i.ecywang.com/upload/1/img2.baidu.com/it/u=3917959868,2018923084&fm=26&fmt=auto&gp=0.jpg)
已知cos(派/6-x)=根号3/3求cos(5/6派 x)-sin平方(x-派/6)的值
图片尺寸3264x1952![高等数学题目:sin2x/cos2x*sin(π/4-x)/cos(π/4-x)化简](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=2194776740,2382342561&fm=26&fmt=auto&gp=0.jpg)
高等数学题目:sin2x/cos2x*sin(π/4-x)/cos(π/4-x)化简
图片尺寸981x741![已知cosα=2/3,α∈(3π/2,2π),求cos(π/6 α),cos](https://i.ecywang.com/upload/1/img0.baidu.com/it/u=1578772072,3252460875&fm=26&fmt=auto&gp=0.jpg)
已知cosα=2/3,α∈(3π/2,2π),求cos(π/6 α),cos
图片尺寸780x1052![应为sin5π/3=-sinπ/3 追答: 追问: 怪不得我也看不懂,cos也是错的么](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=3133031667,3738261773&fm=26&fmt=auto&gp=0.jpg)
应为sin5π/3=-sinπ/3 追答: 追问: 怪不得我也看不懂,cos也是错的么
图片尺寸972x1296![已知cos(π-a)=根号3,求cos(5π-a)-sin*(a-π](https://i.ecywang.com/upload/1/img1.baidu.com/it/u=3539340107,3310772790&fm=26&fmt=auto&gp=0.jpg)
已知cos(π-a)=根号3,求cos(5π-a)-sin*(a-π
图片尺寸2048x1536